SDCMS后台绕过直接进入,一种不常见的设计失误案例漏洞预警 -电脑资料

时间:2017-09-04 03:34:10
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简要描述:

SDCMS后台绕过直接进入:测试版本2.0 beta2 其他版本未测试

详细说明:

Islogin //判断登录的方法

sub islogin()

if sdcms.strlen(adminid)=0 or sdcms.strlen(adminname)=0 then

dim t0,t1,t2

t0=sdcms.getint(sdcms.loadcookie("adminid"),0) loadcookie

t1=sdcms.loadcookie("islogin")

t2=sdcms.loadcookie("loginkey")

if sdcms.strlen(t0)=0 or sdcms.strlen(t1)=0 or sdcms.strlen(t2)<>50 then //这里判断很 sdcms.strlen(t2)<>50 loginkey 没有任何要求 只需要输入50个即可往下执行

//

sdcms.go "login.asp?act=out"

exit sub

else

dim data

data=sdcms.db.dbload(1,"adminid,adminname,adminpass,islock,groupid,g.pagelever,g.catearray,g.catelever","sd_admin u left join sd_admin_group g on u.groupid=g.id","adminid="&t0&"","") //根据管理员ID查询 ID可控

if ubound(data)<0 then

sdcms.go "login.asp?act=out"

exit sub

else

if instr(data(1,0)&data(2,0),sdcms.decrypt(t1,t2))<0 or data(3,0)=0 then

sdcms.go "login.asp?act=out"

exit sub

else

adminid=data(0,0)

adminname=data(1,0)

admin_page_lever=data(5,0)

admin_cate_array=data(6,0)

admin_cate_lever=data(7,0)

if sdcms.strlen(admin_page_lever)=0 then admin_page_lever=0

if sdcms.strlen(admin_cate_array)=0 then admin_cate_array=0

if sdcms.strlen(admin_cate_lever)=0 then admin_cate_lever=0

if clng(admingroupid)<>0 then

admin_lever_where=" and menuid in("&admin_page_lever&")"

end if

sdcms.setsession "adminid",adminid

sdcms.setsession "adminname",adminname

sdcms.setsession "admingroupid",data(4,0)

end if

end if

end if

else

data=sdcms.db.dbload(1,"g.pagelever,g.catearray,g.catelever","sd_admin u left join sd_admin_group g on u.groupid=g.id","adminid="&adminid&"","")

if ubound(data)<0 then

sdcms.go "login.asp?act=out"

exit sub

else

admin_page_lever=data(0,0)

admin_cate_array=data(1,0)

admin_cate_lever=data(2,0)

if sdcms.strlen(admin_page_lever)=0 then admin_page_lever=0

if sdcms.strlen(admin_cate_array)=0 then admin_cate_array=0

if sdcms.strlen(admin_cate_lever)=0 then admin_cate_lever=0

if clng(admingroupid)<>0 then

admin_lever_where=" and menuid in("&admin_page_lever&")"

end if

end if

end if

end sub

漏洞证明:

看看操作COOKIE的函数

public function loadcookie(t0)

loadcookie=request.cookies(prefix&t0)

end function

public sub setcookie(byval t0,byval t1)

response.cookies(prefix&t0)=t1

end sub

prefix

'变量前缀,如一个空间下多次使用本程序的话,请每个程序配置不同的值

dim prefix

prefix="1Jb8Ob"

'这个值访问一下admin/login.asp?act=out 便可得到 在COOKIE里

sub out

sdcms.setsession "adminid",""

sdcms.setsession "adminnam

e",""

sdcms.setsession "admingroupid",""

sdcms.setcookie "adminid",""

sdcms.setcookie "loginkey",""

sdcms.setcookie "islogin",""

sdcms.go "login.asp"

end sub

利用方法:设置cookie prefixloginkey 50个字符 prefixislogin 随意 循环下prefixadminid 即可 默认1 然后访问后台,就可以了!

修复方案:

修改函数!

SDCMS后台绕过直接进入,一种不常见的设计失误案例漏洞预警 -电脑资料

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